Y=40x^2-10

Solution for Y=40x^2-10 equation:

=40Y^2-10

We move all terms to the left:

-(40Y^2-10)=0

We get rid of parentheses

-40Y^2+10=0

a = -40; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-40)·10
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*-40}=\frac{-40}{-80}
=1/2
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*-40}=\frac{40}{-80}
=-1/2
$